+525 The gates of an amusement park are closely monitored to determine whether the number of people in the amusement park ever poses a safety hazard.
On a certain day, the rate at which people enter amusement park is modeled by the function e(x)=0.03x^3+2 where the rate is measured in hundreds of people per hour since the gates opened. The rate at which people leave the amusement park is modeled by the function l(x)=0.5x+1 , where the rate is measured in hundreds of people per hour since the gates opened.
What does (e−l)(4) mean in this situation?
+128475
Hard to read these functions, but I think we have
e(x) = .03x^3 + 2
l (x) = .5x + 1
So .. ( e - l) = [ .03x^3 + 2 ] - [ .5x + 1 ] = .03x^3 - .5x + 1
So
(e - l ) (4) = .03(4)^3 - .5(4) + 1 = .92 ...this is in hundreds, so it converts to 92 people
So....this means that 4 hours after the park opens, the rate that the number of people is changing is 92 people per hour
