In triangle ABC, point P is on side BC such that PA = 13, PB = 14, PC = 4, and the circumcircles of triangles APB and APC have the same radius. Find the area of triangle ABC.
I'm getting that the area of triangle ABC is 92.
i got 12 for the height and we know the base is 18 (14 + 4).
so 12*18*1/2 = 108
+34 
