+0  
 
-1
270
2
avatar+444 

Compute     16C15

Mr.Owl  Oct 19, 2017
 #1
avatar+444 
+2

Ahhh, I got the answer:

 

\(\dbinom{16}{15}=\dbinom{16}{1}=\boxed{16}.\)

Mr.Owl  Oct 19, 2017
 #2
avatar+93866 
+2

16C15 = 16   when you get more familiar with this the answer will become obvious to you.

It is like saying how many ways can 15 obects be selected from 16 (order doesn't count)

and this is the same as saying how many ways can one object be omitted from the original 16. There is 16 objects so there are obviously 16 ways that one can be left out.

16Cr = 16C(16-r)   it is always symmetrical like this. 

 

There are different ways to enter this on the web2 calc 

I would do it like this (if I had needed to)

 

nCr(16,15)=

nCr(16,15) = 16

Melody  Oct 19, 2017

8 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.