+0  
 
+1
217
1
avatar+717 

There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

In how many games does a girl play against another girl?

SmartMathMan  Jan 16, 2018
 #1
avatar+92744 
+1

Note that  we have 5 girls....and we want to choose any 2 for a game....so

 

C (5.2)  =  10  games

 

cool cool cool

CPhill  Jan 17, 2018

15 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.