There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

In how many games does a girl play against another girl?

SmartMathMan  Jan 16, 2018

1+0 Answers


Note that  we have 5 girls....and we want to choose any 2 for a game....so


C (5.2)  =  10  games


cool cool cool

CPhill  Jan 17, 2018

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