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Determine if the graph of the equation below is a parabola, circle, ellipse, hyperbola, point, line, two lines, or empty. $x^2 + 2y^2 - 6x - 20y + 59 = 12$

 Dec 9, 2018

Best Answer 

 #1
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It is an ellispe because

putting it into conic form we have 

\((x^2-6x+9)+2(y^2-10y+25)=12\)

\((x-3)^2+2(y-5)^2=12\)

\( \frac{(x-3)^2}{12}+\frac{(y-5)^2}{6}=1\)

you can also put it into desmos to see the graph of it

 Dec 9, 2018
 #1
avatar
+1
Best Answer

It is an ellispe because

putting it into conic form we have 

\((x^2-6x+9)+2(y^2-10y+25)=12\)

\((x-3)^2+2(y-5)^2=12\)

\( \frac{(x-3)^2}{12}+\frac{(y-5)^2}{6}=1\)

you can also put it into desmos to see the graph of it

Guest Dec 9, 2018

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