In a sale Tommy bought a kettle and a toaster. He paid a total of $105. The amount paid for the kettle is 2/5 the cost of the toaster. The total price before the discount should have been $133. The toaster was reduced by 20%. How much was the kettle reduced by?
Note:If we reduce a by b%, then final amount will
be = a - ab/100
Let the cost of the toaster is $x.
Since the amount paid for the kettle is 2/5 the
cost of the toaster, then the cost of kettle will
be $ 2x/5.
According to the given conditions,
x + 2x/5 = 105
Or, 7x/5 = 105
Or, x = 105*5/7 = 75
So, the cost of the toaster is = $75 and the cost of the kettle is = $(105-75) =$30.
Since the toaster was reduced by 20%, then before reduction its price was
= $ 100*75/(100-20) = $ 93.75
Thus before reduction the price of kettle was = $(133-93.75) = $ 39.25
So, the percentage of reduction of the price of kettle is
= ((39.25 - 30)*100)/30 = 23.5669%
Therefore required answer is 23.5669%.