If $(2x + 3y)^2 = 4$ and $xy = -5$, what is the value of $4x^2 + 9y^2$?
Solving the system (2x + 3y)^2 = 4 and xy = -5, we get x = -(sqrt(14) + 1)/2 and y = (sqrt(14) - 1)/3.
Then 4x^2 + 9y^2 = 4*(-(sqrt(14) + 1)/2)^2 + 9((sqrt(14) - 1)/3)^2 = 30.
(2x+3y)2=4x2+12xy+9y2=4x2−60+9y2=4
4x2+9y2=64.