Given that the point (8,8) is on the graph of y=\frac 14f\left(\frac 12x\right) there is one point that must be on the graph of y=f(x). What is the sum of coordinates of that point?

Guest Mar 27, 2018

#1**+1 **

Given that the point (8, 8) is on the graph of \(y=\frac 14f\left(\frac 12x\right)\) , there is one point that must be on the graph of y = f(x) . What is the sum of the coordinates of that point?

\(8=\frac 14f\left(\frac 12(8)\right)\\~\\ 8=\frac 14f\left(4\right)\\~\\ 4\cdot8=f\left(4\right)\\~\\ 32=f\left(4\right)\\~\\ f\left(4\right)=32\)

So (4, 32) must be a point on the graph of y = f(x) .

4 + 32 = 36

hectictar Mar 27, 2018