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Given that the point (8,8) is on the graph of y=\frac 14f\left(\frac 12x\right) there is one point that must be on the graph of y=f(x). What is the sum of coordinates of that point?

Guest Mar 27, 2018
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Given that the point  (8, 8)  is on the graph of  $$y=\frac 14f\left(\frac 12x\right)$$ , there is one point that must be on the graph of  y = f(x) . What is the sum of the coordinates of that point?

$$8=\frac 14f\left(\frac 12(8)\right)\\~\\ 8=\frac 14f\left(4\right)\\~\\ 4\cdot8=f\left(4\right)\\~\\ 32=f\left(4\right)\\~\\ f\left(4\right)=32$$

So  (4, 32)  must be a point on the graph of  y = f(x) .

4 + 32  =  36

hectictar  Mar 27, 2018

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