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The letters in the word SLEEP are arranged.  How many different arrangement begin with the letter E?

 Oct 30, 2019
 #1
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4! (Because E is repeated so we just take 1) P,E,L,S (4 letters) So they can be arranged 4!=24

24

 Oct 30, 2019
 #2
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Another way:

 

SLEEP has 5 letters. 5! / 2! =60 permutations. Or 60 / 5 letters =12 for each letter. Since we have 2 of the same letter, then 2 x 12 = 24.

 Oct 30, 2019
 #3
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Let's assume that the letter starts with E, because that's what we're looking for.

 

There are four other letters, S, L, E, and P.

Since none of them are the same letter, we can simply do 4! and get 24.

 

NOTE:

Let's say the word was SEEEP.

Then the letters would be S, E, E, and P.

This would make 4!/2!, because we are repeating E twice.

 

You are very welcome!

:P

 Oct 30, 2019

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