The quadratic \(x^2+1300x+1300\) can be written in the form \((x+b)^2+c\), where b and c are constants. What is \(\frac{c}{b}\)?
x^2 + 1300x + 1300 complete the square on x
Take 1/2 of 1300 = 650.....square it = 422500
Add it and subtract it
x^2 + 1300x + 422500 + 1300 - 422500
Factor the first three terms and simplify
(x + 650)^2 - 421200
c = - 421200 b = 650
c / b = - 421200 / 650 = -648
+1206 
