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# Help

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How do I solve 2x - x/8 + 5 = 35

Oct 26, 2017

#1
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$$\frac{2x-x}{8}+5=35$$

2x-x=x

$$\frac{x}{8}+5=35$$

To get x by itself, multiply everything by 8.

$$x+40=280$$

Subtract 40 from both sides.

$$x+40-40=280-40$$

$$x=240$$

To verify, plug into the original equation.

$$\frac{2(240)-240}{8}+5=35$$

Simplify.

$$\frac{480-240}{8}+5=35$$

$$\frac{240}{8}+5=35$$

$$\frac{240}{8}=\frac{120}{4}=\frac{60}{2}=\frac{30}{1}$$

30/1=30

$$30+5=35$$

$$35=35$$

This is true, so x is 240.

Oct 26, 2017
#2
+95859
+1

I'm solving a slightly different problem than AT.......which interprtation is correct - who knows??

2x  - x / 8  + 5    =  35      subtract 5 from both side

2x - x / 8  =  30              multiply through by 8

16x - x  =  240

15x  = 240   divide both sides by 15

x  = 16

Thanks to AT.....for pointing out my silly error....!!!

Oct 26, 2017
edited by CPhill  Oct 26, 2017
#3
+771
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Hey CPhill, on your third step where you multiply through by 8, the 2x wouldn't become 16x. It would stay x, as it would multiply by 8 then also divide by 8.

The way you did it, the answer doesn't work when plugged in.

2(2)-2/8 +5=35

4-2/8+5=35

2/8+5=35

1/4+5=35

21/4=35

This is not true, so x can not equal 2.

Do you see what I mean?

edited by AdamTaurus  Oct 26, 2017
edited by AdamTaurus  Oct 26, 2017
#4
+95859
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Yeah...I made a slight error...let me fix that.....thanks, AT  !!!

Oct 26, 2017
#5
+771
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You're welcome, CPhill. Keeep doing the good work you do.

#6
0

2x-x/8+5=35

2x-x/8=30

2x=30+x/8

16x/8=30+x/8

15x/8=30

x+7/8=30

x=30-7/8

x=29+1/8

$$x=29\frac{1}{8}=\frac{232}{8}$$

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Oct 26, 2017