+773 The vertex of the parabola described by the equation 3y=2x^2-16x+18 is (m, n). What is m+n?
+23246 Let's find the vertex by completing the square.
First, move the 18 to the other side: 3y - 18 = 2x2 - 16x
Factor out the 2: 3y - 18 = 2(x2 - 8x)
Complete the square: 3y - 18 = 2(x2 - 8x + 16) - 32
Move the -18 3y = 2(x - 4) - 14
Divide both sides by 3: y = (2/3)(x - 4)2 - 14/3
The vertex is (4, -14/3)
