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What is the $x$-coordinate of the point on the $x$-axis that is equidistant from points $A( -2, 0)$ and $B(0,4)$?

 Jul 7, 2019
 #1
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It is on the x-axis , so the y coordinate will be '0'

x, 0

Distance from point a=    sqrt ((-2-x)^2 + 0^2)

 

 equate to the distance from point b

         sqrt(0-x)^2 + (4-0)^2

 

x^2 +16 =  4 +4x + x^2

12 = 4x

x = 3

 

since y = 0    the point is     3,0    and the distance from each point is 5

 Jul 7, 2019

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