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If \(\displaystyle{f(x)=x^{(x+1)}(x+2)^{(x+3)}}\), then find the value of \(f(0)+f(-1)+f(-2)+f(-3)\).

 Feb 17, 2019
 #1
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f(x)=x^(x+1)*(x+2)^(x+3)

f(0)=0^(0+1)*(0+2)^(0+3)

f(0)=0^1*2^3

f(0)=0*8

f(0)=0

f(-1)=1

f(-2)=0

f(-3)=1/9

f(0)+f(-1)+f(-2)+f(-3)=10/9

0+1+0+(1/9)=10/9

 

 

winkwinkwink

 Feb 17, 2019

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