The lengths of two sides of a triangle are 33 units and 42 units. The third side also has an integral length. What is the least possible number of units in the perimeter of the triangle?
Hey- Check out this link: https://web2.0calc.com/questions/inequalities-in-triangles
Lie the two given lengths on top of each other. If you join them with a third length of 9 units you will have a straight line, but if you increase the length of the third length by 1 unit while keeping the ends joined you will get a triangle. Hence shortest third length is 10 units. I'm sure you can add up the lengths to get the perimeter.