+0  
 
0
255
1
avatar+4269 

Help.

NotSoSmart  Sep 22, 2017
 #1
avatar+92367 
+1

 

1.  Here's how we can find the answer to the first one...if y varies directly with x...we have...

 

24  = k * 6        divide both sides by 6

 

k  = 4

 

So.....every  successive "y"  value  in the table should be  4 times of its associated  x value...is this true.....it looks like it....so....

 

k  = 4  and y  = 4x

 

 

 

2. For the second one...the answer is no

Note....if   x   = 3 , then y  = -13

And..if  x  = 6 , then y  = -20 

And if x  = 9, then y  = -27...... 

If this were a direct variation like the first problem, successive y values would be multiples of the first....but this isn't so   

[ Look at the first problem....x and y both change by multiples of  3   ]

 

 

3.  y = kx     .....so...... 

    2.52  = k  (8.4)    divide both sides by   8.4

    2.52 / 84  = k  =  3/10

 

So    when x  = 2.7....we have that

 

y  =  (3/10) 2.7

y  =  8.1 / 10    =   0 .81

 

 

 

cool cool cool

CPhill  Sep 22, 2017

16 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.