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Let a and b be positive real numbers, with a>b. Compute \(\frac{1}{ba} + \frac{1}{a(2a - b)} + \frac{1}{(2a - b)(3a - 2b)} + \frac{1}{(3a - 2b)(4a - 3b)} + \dotsb.\)

 Dec 8, 2018

Take a subsequence of N terms of this.


Split each term up using partial fractions


You'll see this reveals that the sequence is a telescoping sequence.


After the sum only part of the Nth term remains


\(\dfrac{N}{b (a N+b (-N)+b)}\)


Taking the limit of this as N goes to infinity results in



 Dec 8, 2018

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