Which of the following is largest?
\(\large A = 998 \times 999^{1000} \\ \\ \large B = 999 \times 999^{999} \\ \\ \large C = 997 \times 999^{1001} \\ \\ \large D = 996 \times 998^{1000}\)
+680 first compare A and B. At first glance we con obviously tell that A is larger because B is only \(999^{1000}\)while A is 998 \(\times\) B. So we have one inequality already A > B.
Now let's compare B and C. B is \(999^{1000}\) and C is definetely greater than that so another inequality:
C > B.
Now let's compare C and D: If you estimate, then C is greater.
C > D.
but we aren't done!!! A may be greater than B but it may be smaller than C or D. When we compare A and C then C is greater by a lot.
so C > A.
Now we compare all our inequalities: B < A < C and D < C.
Let's compare A and D. and we found that A is larger.
D < A.
Last one: is D smaller than B? D is in fact smaller than B.
This is the final solution: \(\boxed{D < B < A < C}\)
Yikes!! (I may have done some estimation wrong.)
