Help.

1. Both will be functions.....no single "x" will have two different "y's" associated with it.....it is "one-to-one"

And a "one-to-one" function's inverse will also be a function, i.e, "one-to-one"

The second answer is the correct one

2.

y = 7x^2 - 3

y + 3 = 7x^2

[ y + 3 ] / 7 = x^2

±√ [ (y + 3) / 7 ] = x

±√ [ ( x + 3) / 7 ] ⇒ inverse