#1**+2 **

Hi Guest!

We use: \(x^3-y^3=(x-y)(x^2+xy+y^2) \)

We already know \( (x-y)\) and \(x^2+y^2\)

We can plug the known values in, and we get:

\(6(24+xy)=x^3-y^3\)

To solve for xy, we use: \((x-y)^2=x^2-2xy+y^2\)

This means that \(6^2=24-2xy\)

Solving for xy, we get:

\(36=24-2xy\\ 12=-2xy\\ xy=-6\)

Now we can plug this into the original expression:

\(6(24-6)=x^3-y^3\\ x^3-y^3=108\)

I hope this helped,

Gavin

GYanggg
May 13, 2018