Help!

Hi Guest!

We use: $x^3-y^3=(x-y)(x^2+xy+y^2)$

We already know $(x-y)$ and $x^2+y^2$

We can plug the known values in, and we get:

$6(24+xy)=x^3-y^3$

To solve for xy, we use: $(x-y)^2=x^2-2xy+y^2$

This means that $6^2=24-2xy$

Solving for xy, we get:

$36=24-2xy\\ 12=-2xy\\ xy=-6$

Now we can plug this into the original expression:
$6(24-6)=x^3-y^3\\ x^3-y^3=108$

I hope this helped,

Gavin