A 20 N force acts on an object. The horizontal component of this force has a magnitude of 12 N. What is the angle the force made with the horizontal?
a) 53.13°
b) 36.87°
c) 23.58°
d) 66.42°
We can solve this :
20 cos (theta) = 12
cos (theta) = 12/20
cos (theta) = 3/5
arccos (3/5) = 53.13° = theta
+956 
