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A 20 N force acts on an object. The horizontal component of this force has a magnitude of 12 N. What is the angle the force made with the horizontal? 

 

a) 53.13°

b) 36.87°

c) 23.58°

d) 66.42°

Julius  May 23, 2018
 #1
avatar+90088 
+2

We can solve this :

 

20 cos (theta)  = 12

 

cos (theta)  = 12/20

 

cos (theta)  =  3/5

 

arccos (3/5)  =  53.13°  = theta

 

 

cool cool cool

CPhill  May 23, 2018

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