A 20 N force acts on an object. The horizontal component of this force has a magnitude of 12 N. What is the angle the force made with the horizontal?

a) 53.13°

b) 36.87°

c) 23.58°

d) 66.42°

We can solve this :

20 cos (theta) = 12

cos (theta) = 12/20

cos (theta) = 3/5

arccos (3/5) = 53.13° = theta