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How many different three-digit odd numbers can be formed using the digits 3, 4, 5 and 6 if digits cannot be repeated?

 Oct 18, 2018
 #1
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If the number ends in 3

We have three choices for the first digit  and two for the second  = 6 numbers

 

The same logic would apply if the number ended in a "5"

 

So...   12 

 

 

 

cool cool cool

 Oct 18, 2018
edited by CPhill  Oct 18, 2018

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