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The square of an integer is 812 greater than the integer itself. What is the sum of all integers for which this is true?

Guest May 22, 2020

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"The square of an integer is 812 greater than the integer itself. What is the sum of all integers for which this is true?"

Let n be the integer.

Then we have n² - 812 = n or n² - n - 812 = 0

This factors as (n + 28)(n - 29) = 0

You can take it from here.

Alan May 22, 2020

1⁺⁰ Answers

+33659

+3

Best Answer

"The square of an integer is 812 greater than the integer itself. What is the sum of all integers for which this is true?"

Let n be the integer.

Then we have n² - 812 = n or n² - n - 812 = 0

This factors as (n + 28)(n - 29) = 0

You can take it from here.

Alan May 22, 2020

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