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The square of an integer is 812 greater than the integer itself.  What is the sum of all integers for which this is true?

 May 22, 2020

Best Answer 

 #1
avatar+30655 
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"The square of an integer is 812 greater than the integer itself.  What is the sum of all integers for which this is true?"

 

Let n be the integer.

 

Then we have  n2 - 812 = n  or  n2 - n - 812 = 0

 

This factors as  (n + 28)(n - 29) = 0 

 

You can take it from here.

 May 22, 2020
 #1
avatar+30655 
+3
Best Answer

"The square of an integer is 812 greater than the integer itself.  What is the sum of all integers for which this is true?"

 

Let n be the integer.

 

Then we have  n2 - 812 = n  or  n2 - n - 812 = 0

 

This factors as  (n + 28)(n - 29) = 0 

 

You can take it from here.

Alan May 22, 2020

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