+9481 The graph does not touch the x axis anywhere. That means there are no points on the graph that have a y value of 0 . There are no x values that cause y to be zero.
So... there are no real solutions to this equation: f(x) = 0
+118690 Hectictar is correct of course but the question is very badly worded becasue this is the equaton of
\(y=(x-2)^2+6\)
Which has an infinite number of solution pairs.
BUT
\(0=(x-2)^2+6\) has no solutions
+2446 I believe for quadratics that "solutions" refers to the zeros of the particular function. Nonetheless, I also agree that it can cause some ambiguity and avoiding that language is preferrable. It is better to either use "zeros" or "roots."
