+0  
 
-1
213
3
avatar+2509 

Help.

NotSoSmart  Nov 17, 2017
 #1
avatar+7155 
+2

The graph does not touch the  x  axis anywhere. That means there are no points on the graph that have a  y  value of  0 . There are no  x  values that cause   y  to be zero.

 

So... there are no real solutions to this equation:   f(x) = 0

hectictar  Nov 17, 2017
 #2
avatar+92781 
+2

Hectictar is correct of course but the question is very badly worded becasue this is the equaton of 

 

\(y=(x-2)^2+6\)

 

Which has an infinite number of solution pairs.

 

BUT

\(0=(x-2)^2+6\)       has no solutions

Melody  Nov 18, 2017
 #3
avatar+2117 
+1

I believe for quadratics that "solutions" refers to the zeros of the particular function. Nonetheless, I also agree that it can cause some ambiguity and avoiding that language is preferrable. It is better to either use "zeros" or "roots."

TheXSquaredFactor  Nov 18, 2017

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