#1**+2 **

The graph does not touch the x axis anywhere. That means there are no points on the graph that have a y value of 0 . There are no x values that cause y to be zero.

So... there are no real solutions to this equation: f(x) = 0

hectictar Nov 17, 2017

#2**+2 **

Hectictar is correct of course but the question is very badly worded becasue this is the equaton of

\(y=(x-2)^2+6\)

Which has an infinite number of solution pairs.

BUT

\(0=(x-2)^2+6\) has no solutions

Melody Nov 18, 2017

#3**+1 **

I believe for quadratics that "solutions" refers to the zeros of the particular function. Nonetheless, I also agree that it can cause some ambiguity and avoiding that language is preferrable. It is better to either use "zeros" or "roots."

TheXSquaredFactor
Nov 18, 2017