A sphere is inscribed in a cube with edge length 9 inches. Then a smaller cube is inscribed in the sphere. How many cubic inches are in the volume of the inscribed cube? Express your answer in simplest radical form.
The radius of the sphere will be 9 inches
And this will be the length of the "long" diagonal drawn from the bottom vertex of the small cube to the oppositie top vertex
And we can find the edge length , e, of this cube as
e^2 + 2e^2 = 9^2
3e^2 = 81
e^2 = 27
e = √27
So...the volume of the smaller cube is
e^3 = (√27)^3 =
27√27 =
81√3 in^3