. Let ABCD be a convex quadrilateral with AB = 11, BC = 7, CD = 11, DA = 26. If ∠BEC = 120◦ , where E is the point of intersection of AB and CD, find BE and C
The first thing you have to do is draw a pic.
You probably won't get it right the first time.
You have to tweak it, and redraw it, a few times until it is right.
Have you done that?
If so, upload a pic of it, or just describe what you pic looks like.
after that you can use cosine rule twice and then solve them the best you can simultaneously
I won't say more until you have contributed something of your own.
Hello! Thank you for the tip!! So far. I have drawn a large triangle with a similar smaller triangle inside. I will attemp to upload the picture, however I am new to the forum and am not sure of the tools used. for reference, AED is the larger triangle will BEC is the smaller and similar triangle inside. I assumed that it was isoceles, but i am probably wrong 🥲. Because I am at an ameuteur geometry level, I attempted to solve this problem with similar triangles, but that led to the solution of 77/19, which I am decently sure is incorrect. Any help is appreciated. Thanks again!
Thanks for that great interaction.
I think you have drawn the triangle correctly.
It does not work out to be isosceles.
I let the two unknown lengths be x and y
then I formed two equations using the cosint rule, one beginning with 26^2= and the other with 7^2=
then I solved them simultateously (with subtraction) to get an expression for y in terms of x.
then i subed back into an original equation to get two numbers for x,
[One is actually x and the other is y becasue the terms are interchangeable]
See how much that helps.
* Note that my method may not be the best method.