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# help

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There are numbers A and B for which
A/(x - 1) + B/(x + 1) = (x + 8)/(x^2 - 1)
for every number $x\neq\pm1$. Find A-B

Aug 7, 2021

#1
+126
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Solution:

Combining denominators on left, and then removing it from both sides gives

A(x+1) + B(x-1) = x + 8

Two equations can be found from this:

A + B = 1

A - B = 8

Aug 7, 2021