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There are numbers A and B for which
A/(x - 1) + B/(x + 1) = (x + 8)/(x^2 - 1)
for every number $x\neq\pm1$. Find A-B

 Aug 7, 2021
 #1
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Answer: 8

 

Solution:

Combining denominators on left, and then removing it from both sides gives

 

A(x+1) + B(x-1) = x + 8

 

Two equations can be found from this:

 

A + B = 1

A - B = 8

 Aug 7, 2021

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