Find the constant term in the expansion of ( x^2 + 1/x )^4.
Answer: There is no constant term.
Solution:
I expanded it using the Binomial Theorem:
\(x^8 + 4x^5 + 6x^2 + \frac4x + \frac1{x^4}\)
There appears to be no constant term.
I see. Thanks to you and cPhill. I hope you all have a nice day!
Thx, Viola....you, too !!!!
There is no constant term.....the expansion is
x^8 + 4 x^5 + 1/x^4 + 6 x^2 + 4/x
+307 
