Find the constant term in the expansion of ( x^2 + 1/x )^4.

Answer: There is no constant term.

Solution:

I expanded it using the Binomial Theorem:

\(x^8 + 4x^5 + 6x^2 + \frac4x + \frac1{x^4}\)

There appears to be no constant term.

I see. Thanks to you and cPhill. I hope you all have a nice day!

Thx, Viola....you, too !!!!

There is no constant term.....the expansion is

x^8 + 4 x^5 + 1/x^4 + 6 x^2 + 4/x