+0  
 
+2
127
4
avatar+165 

Find the constant term in the expansion of ( x^2 + 1/x )^4.

 Jul 14, 2021
 #1
avatar+126 
+6

Answer: There is no constant term.

 

Solution:

I expanded it using the Binomial Theorem:

 

\(x^8 + 4x^5 + 6x^2 + \frac4x + \frac1{x^4}\)

 

There appears to be no constant term.

 Jul 14, 2021
 #3
avatar+165 
+2

I see. Thanks to you and cPhill. I hope you all have a nice day!

viola  Jul 14, 2021
 #4
avatar+121065 
+1

Thx, Viola....you, too  !!!!

 

 

cool cool cool

CPhill  Jul 14, 2021
 #2
avatar+121065 
+3

There is no constant term.....the  expansion is

 

x^8 + 4 x^5 + 1/x^4 + 6 x^2 + 4/x

 

 

cool cool cool

 Jul 14, 2021

43 Online Users

avatar