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# help

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Find the constant term in the expansion of ( x^2 + 1/x )^4.

Jul 14, 2021

#1
+86
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Answer: There is no constant term.

Solution:

I expanded it using the Binomial Theorem:

$$x^8 + 4x^5 + 6x^2 + \frac4x + \frac1{x^4}$$

There appears to be no constant term.

Jul 14, 2021
#3
+165
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I see. Thanks to you and cPhill. I hope you all have a nice day!

viola  Jul 14, 2021
#4
+121008
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Thx, Viola....you, too  !!!!

CPhill  Jul 14, 2021
#2
+121008
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There is no constant term.....the  expansion is

x^8 + 4 x^5 + 1/x^4 + 6 x^2 + 4/x

Jul 14, 2021