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Assuming that \($y\neq 1/2,$ \) simplify the expression \(\dfrac{12y^3-6y^2}{2y-1}. \)
Simplify the following:
(12 y^3 - 6 y^2)/(2 y - 1)
Factor common terms out of 12 y^3 - 6 y^2.
Factor 6 y^2 out of 12 y^3 - 6 y^2:
(6 y^2 (2 y - 1))/(2 y - 1)
Cancel common terms in the numerator and denominator of (6 y^2 (2 y - 1))/(2 y - 1).
(6 y^2 (2 y - 1))/(2 y - 1) = (2 y - 1)/(2 y - 1)×6 y^2 = 6 y^2:
6 y^2
