Osman kept 720 sweets in three jars. The ratio of the number of sweets in jar A to the number of sweets in jars B and C was 1 : 3. He gave away 4/9 of the sweets in jar A, 30 sweets from Jar B and 60 sweets from jar C. After that, he bought another 50 sweets and kept them in jar C. The ratio of the number of sweets in jar A to the number of sweets in jar B became 1 : 2. How many sweets were there in jar C in the end?
+128407 A originally contains = 1 / ( 1+3) (720) = (1/4) ( 720) = 180
B + C = 540
C = 540 - B
And (4/9) 180 = 80 were given away from jar A....so it now contains 100 sweets
And B now contains B - 30
So we know that
100 / ( B - 30) = 1 /2 (cross-multiply)
200 = B - 30
So B originally contained 230
And C originally contained 540 - 230 = 310
And 60 of these were given away and 50 were added
So C finally contains 310 - 60 + 50 = 300
