+0  
 
0
692
6
avatar+273 

I am just looking for help with these three. Any help is appreciated help. 

 Apr 16, 2018
 #1
avatar+2448 
+1

For the second one I got 8/13 

and the third one, I'm not sure if I'm right but I got:

P (A or B)=17/45

P (B or C)= 20/45

P (D or C)= 22/45

 Apr 16, 2018
 #3
avatar+128475 
+1

GREAT JOB, RP    !!!!

 

 

cool cool cool

CPhill  Apr 16, 2018
 #4
avatar+273 
+2

Good job! Thanks

LaughingFace  Apr 16, 2018
 #2
avatar+128475 
+2

Second one

 

We have 13 cards

 

P ( 5  or D )  = P(5) + P(D)  - P  (5 and D)

                        2/13  +  7/13  -   1/13

                              8/13

 

Last one

 

P ( A or B)  =   P(A)  +  P (B)  -  P (A  ∩ B)

                  =     8/45  + 11/45  -  2/45            

                  =     17/45

 

P(B or C)  =   P(B)  + P(C)  - P(B  ∩C)

                  = 11/45 + 10/45  - 1/45

                 =  20/45

 

 

P (C or D)  = P(C)  + P (D)  - P (C  ∩ D)

                  =  10/45  + 12/45  - 0/45

                  =   22/45

       

 

cool cool cool

 Apr 16, 2018
 #5
avatar+273 
+1

any idea about number 1?

LaughingFace  Apr 16, 2018
 #6
avatar+128475 
+1

Hectictar has answered the first one here :

 

https://web2.0calc.com/questions/please-help-ty_3

 

 

cool cool cool

 Apr 16, 2018

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