Two angles of an equilateral triangle have measures $3x^{\circ}+ 27^{\circ}$ and $2y^{\circ} - 4^{\circ}$. Find $x + y.$
+248 \( 3x^{\circ}+ 27^{\circ}, \space2y^{\circ} - 4^{\circ} \)
An equilateral triangle is a triangle where all the algles are the same, so they all measure 60 degrees.
The equations 3x+27=60 and 2y-4=60 can be made because they are the measures of the angles and both of them are equil to 60.
The equations can be solved to find x and y
3x+27=60
3x=33 subtract 27 from each side
x=11 divide by 3
2y-4=60
2y=64 add 4 to both sides
y=32 divide by 2
So x+y=11+32=43
