+0

# help

0
236
2
+1040

compute$$\dbinom{4}{0}+\dbinom{4}{1}+\dbinom{4}{2}+\dbinom{4}{3}+\dbinom{4}{4}$$

Oct 21, 2018

#1
+129
+1

Well,

4 choose 0 = 1,

4 choose 1 = 4,

4 choose 2 = 6,

4 choose 3 = 4 choose 1 = 4,

4 choose 4 = 4 choose 0 = 1,

1+4+6+4+1 = 16

16, and good luck!

Oct 21, 2018
#2
+23043
+9

compute:

$$\dbinom{4}{0}+\dbinom{4}{1}+\dbinom{4}{2}+\dbinom{4}{3}+\dbinom{4}{4}$$

$$\begin{array}{|rcll|} \hline (1+1)^4 &=& \dbinom{4}{0}\cdot 1^4\cdot 1^0 + \dbinom{4}{1}\cdot 1^3\cdot 1^1 + \dbinom{4}{2}\cdot 1^2\cdot 1^2 + \dbinom{4}{3}\cdot 1^1\cdot 1^3 + \dbinom{4}{4}\cdot 1^0\cdot 1^4 \\\\ (1+1)^4 &=& \dbinom{4}{0}+\dbinom{4}{1}+\dbinom{4}{2}+\dbinom{4}{3}+\dbinom{4}{4} \\\\ 2^4 &=& \dbinom{4}{0}+\dbinom{4}{1}+\dbinom{4}{2}+\dbinom{4}{3}+\dbinom{4}{4} \\\\ 16 &=& \dbinom{4}{0}+\dbinom{4}{1}+\dbinom{4}{2}+\dbinom{4}{3}+\dbinom{4}{4} \\ \hline \end{array}$$

Oct 22, 2018