+128460 Note that by ASA, triangles ACN and XCN are congruent
This means that AN = XN = 5
And AN + XN = AX = 10
So...in triangle AXB.....M is the midpoint of AB and N is the midpoint of AX
But.....if these sides are split in a 1:1 ratio....then a segment connecting MN must be parallel to base BX
Therefore....we have that
AN / MN = AX / BX
5 / MN = 10 / 14
5 / MN = 5 / 7
This implies that MN = 7
