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My question is based on Similar Triangles

 

 Oct 10, 2018
 #1
avatar+99585 
+1

Note that by ASA, triangles ACN  and XCN  are congruent

This means that  AN = XN  =  5

And AN + XN  = AX   = 10

 

So...in triangle  AXB.....M  is the midpoint of AB  and N  is the midpoint of AX

 

But.....if these sides are split in a 1:1 ratio....then a segment  connecting MN  must be parallel to base  BX

 

Therefore....we have that

 

AN / MN  = AX / BX

 

5  / MN = 10 / 14

 

5 / MN  = 5 / 7   

 

This implies that  MN   = 7

 

 

cool cool cool

 Oct 10, 2018
 #2
avatar+464 
+1

Thank you so much CPhill

 Oct 10, 2018

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