We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
256
1
avatar+1046 

For specific positive numbers $m$ and $n$, the quadratics $16x^2+36x+56$ and $(mx+n)^2$ differ only in their constant term. What is $mn$?

 Jun 10, 2018
 #1
avatar+21978 
+1

For specific positive numbers $m$ and $n$,
the quadratics $16x^2+36x+56$ and $(mx+n)^2$ differ only in their constant term.
What is $mn$?

 

\(\begin{array}{|lrcll|} \hline 16x^2+{\color{red}36}x+56 \\ &&& (mx+n)^2 \\ &&=& m^2x^2+{\color{red}2mn}x+n^2 \\ \Rightarrow & 36 &=& 2mn \\ & mn &=& \frac{36}{2} \\ & \mathbf{mn} & \mathbf{=} & \mathbf{18} \\ \hline \end{array}\)

 

laugh

 Jun 11, 2018

19 Online Users

avatar
avatar
avatar