Let f be defined by
\(f(x) = \left\{ \begin{array}{cl} 2-x & \text{ if } x \leq 1, \\ 2x-x^2 & \text{ if } x>1. \end{array} \right.\)
Calculate \(f^{-1}(-3)+f^{-1}(0)+f^{-1}(3)\).
The first condition should be followed for numbers that are lower than or equal to 1.
The second condition should be used for numbers that are higher than 1.
Since f^-1(-3) follows the first condition, do 2-(-3)=5.
Similarly, since f^-1(0) also follows the first condition, do 2-0=2.
Since f^-1(3) follows the second condition, as 3 is bigger than 1, do 2*(3)-3^2 = 6-9 = -3
5 + 2 - 3 = 4
The answer is 4.