Let f be defined by
f(x)={2−x if x≤1,2x−x2 if x>1.
Calculate f−1(−3)+f−1(0)+f−1(3).
The first condition should be followed for numbers that are lower than or equal to 1.
The second condition should be used for numbers that are higher than 1.
Since f^-1(-3) follows the first condition, do 2-(-3)=5.
Similarly, since f^-1(0) also follows the first condition, do 2-0=2.
Since f^-1(3) follows the second condition, as 3 is bigger than 1, do 2*(3)-3^2 = 6-9 = -3
5 + 2 - 3 = 4
The answer is 4.