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# help

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85
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solve for x$$(x-4)^3=\left(\frac18\right)^{-1}$$

Apr 21, 2019

#1
+103069
+1

Note that     (1/8)^(-1)   =  8

So

(x - 4)^3  = 8         take the cube root of each side

x - 4  =  (8)^(1/3)

x - 4   =  2         add 4 to both sides

x  =  6

Apr 21, 2019
#2
+128
-1

First figure out the right hand side.

1/8 to the power of -1 is the same thing as 8. Now, (x-4)^3 = 8

After this, get the cube root to the other side(you know what I mean) to get x-4 = 2.

Add 4 to both sides to get x = 6.

X is 6.

~~Hypotenuisance

Apr 21, 2019