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solve for x\((x-4)^3=\left(\frac18\right)^{-1}\)

 Apr 21, 2019
 #1
avatar+106533 
+1

Note that     (1/8)^(-1)   =  8

 

So

 

(x - 4)^3  = 8         take the cube root of each side

 

x - 4  =  (8)^(1/3)

 

x - 4   =  2         add 4 to both sides

 

x  =  6

 

 

 

 

cool cool cool

 Apr 21, 2019
 #2
avatar+128 
-1

First figure out the right hand side.

 

1/8 to the power of -1 is the same thing as 8. Now, (x-4)^3 = 8

 

After this, get the cube root to the other side(you know what I mean) to get x-4 = 2.

 

Add 4 to both sides to get x = 6.

 

X is 6.

 

~~Hypotenuisance

 Apr 21, 2019

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