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Meyer rolls two fair, ordinary dice with the numbers on their sides. What is the probability that at least one of the dice shows a square number?

this is what i found

(square numbers for this are 1,4,9... and 9 is too big so just 1 and 4)

Guest Jan 17, 2019

ElectricPavlov · Answer 1 · 2019-01-17T05:43:46

36 possible rolls

20 out of 36 will display al least one '1' or at least one '4' 20/36 = 5/9

CPhill · Answer 2 · 2019-01-17T05:54:21

Here's another way to see this

P(at least one square) = 1 - P( no square on either die) =

1 - (4/6) (4/6) =

1 - 16/36 =

[ 36 - 16 ] / 36 =

20 /36 =

5 / 9