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Legolas flips a fair coin 2008 times, and Gimli flips another fair coin 2009 times. What is the probability that Gimli flips more heads than Legolas?

Logic  Nov 25, 2018
 #1
avatar+94183 
+1

 

Legolas flips a fair coin 2008 times, and Gimli flips another fair coin 2009 times. What is the probability that Gimli flips more heads than Legolas?

 

I think it would just be 0.5 

Melody  Nov 25, 2018
 #2
avatar+92856 
+1

I agree with Melody

 

On the first 2008 flips.....each should have the same results

 

On the 2009th flip, Gimli has a (1/2) probability of getting a head

 

This seems too simple....usually, when that's so.....I've not considered some important aspect of the problem.....LOL!!!!

 

 

cool cool cool

CPhill  Nov 25, 2018
 #3
avatar+94183 
+1

It does seem simple but I think it is correct. :/

Melody  Nov 25, 2018
 #4
avatar+92856 
0

LOL!!!!!

 

What do you think our probability of being correct is   ????

 

 

 

cool cool cool

CPhill  Nov 25, 2018
 #5
avatar+94183 
+1

Ummm 90%   LOL 

Melody  Nov 25, 2018
 #6
avatar+135 
0

What about the heads before the last flip? Gimli could've gotten all tails until the 2009th flip, and then Gimli didn't flip more heads than Legolas (unless he also got all tails).

tanmai79  Nov 25, 2018
 #7
avatar
0

The probability of Gimli getting more heads than Legolas is: ~ p = 1 - 1004/1005 =~0.000995 !!

Guest Nov 25, 2018
 #8
avatar+94183 
0

Guest, your answer makes no sense at all.

Melody  Nov 25, 2018

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