Find $a+b+c$, given that $x+y\neq -1$ and \begin{align*} ax+by+c&=x+7,\\ a+bx+cy&=2x+6y,\\ ay+b+cx&=4x+y. \end{align*}
+9481 I think I got it!!!!!!! 
Adding these three equations together will give us another true equation.
Like this...
ax + a + ay + by + bx + b + c + cy + cx = x + 2x + 4x + 6y + y + 7 Then factor it like this...
a(x + 1 + y) + b(y + x + 1) + c(1 + y + x) = 7x + 7y + 7 Divide through by (x + y + 1) .
a + b + c = \(\frac{7x+7y+7}{x+y+1}\)
a + b + c = \(\frac{7(x+y+1)}{x+y+1}\)
a + b + c = 7
*edit*
Also... to show that it produces a true equation when you add them together...let's say...
A = B , C = D , and E = F (And A, B, C, D, E, and F can be expressions.)
A + C + E = A + C + E Now we can substitute B in for A , D in for C , and F in for E .
A + C + E = B + D + F
+2539 The editing label depicting LaTex is a misnomer. This forum doesn’t use LaTeX . It uses TeX
Despite the French sounding name, the “La” in LaTex (probably) comes from (Leslie B. Lamport), the initial developer who wrote advanced scripted algorithms that augmented Donald Knuth’s TeX typesetting program to a more advanced markup and layout program used for publishing.
Translating LaTex into TeX, requires only a slightly higher intelligence than the machine you are using.
\(\text{Find } a+b+c, \text{given that } x+y\neq -1 \\ \text{ and }\\ \begin{align*} ax+by+c&=x+7,\\ a+bx+cy&=2x+6y,\\ ay+b+cx&=4x+y. \end{align*} \)
GA
+9481 I think I got it!!!!!!!
Adding these three equations together will give us another true equation.
Like this...
ax + a + ay + by + bx + b + c + cy + cx = x + 2x + 4x + 6y + y + 7 Then factor it like this...
a(x + 1 + y) + b(y + x + 1) + c(1 + y + x) = 7x + 7y + 7 Divide through by (x + y + 1) .
a + b + c = \(\frac{7x+7y+7}{x+y+1}\)
a + b + c = \(\frac{7(x+y+1)}{x+y+1}\)
a + b + c = 7
*edit*
Also... to show that it produces a true equation when you add them together...let's say...
A = B , C = D , and E = F (And A, B, C, D, E, and F can be expressions.)
A + C + E = A + C + E Now we can substitute B in for A , D in for C , and F in for E .
A + C + E = B + D + F
