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How do you calulate this on a calucator (1+.06) 45

 Aug 21, 2017
 #1
avatar+8079 
+1

How do you calulate this on a calucator (1+.06)^45

 

In the 2.0calculator give

(1+0.06)\([y^x]\) 45 =

result

\((1+0.06)^{45}=13.7646108274409967946\\ 57138048363008541855273127772980523 \)

laugh  !

 Aug 21, 2017
edited by asinus  Aug 21, 2017
 #2
avatar+178 
0

I thought the correct answer should be \((1+0.6)^{45}\approx1532500000\)? (No Offence)

(Oops I accidentally missed a decimal place XD Nevermind the comment above)

Jeffes02  Aug 21, 2017
edited by Jeffes02  Aug 21, 2017
 #3
avatar+99388 
0

The question says 1.06 NOT 1.60 (and it has not been edited) so asinus is correct :)

Melody  Aug 21, 2017

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