+82 Help:
\(1) \sqrt{(x-1)^2} = 1 -x \)
\(2) \sqrt{(y^6)} = -y^3\)
\(3) \sqrt{(1+(\sqrt{2 + \sqrt{n})})} = 2\)
Thanks so much! Please explain. I got the answers but weren't sure if they are correct.
3)
Solve for n:
sqrt(sqrt(sqrt(n) + 2) + 1) = 2
Raise both sides to the power of two:
sqrt(sqrt(n) + 2) + 1 = 4
Subtract 1 from both sides:
sqrt(sqrt(n) + 2) = 3
Raise both sides to the power of two:
sqrt(n) + 2 = 9
Subtract 2 from both sides:
sqrt(n) = 7
Raise both sides to the power of two:
n = 49
Remember that square rooting is equivalent to raising to the power of a half.
1. The operations would cancel leaving x-1
2. This would be (y6)1/2 which, using the power law of indices, would leave y3
3. We would need to square each side, subtract 1 from each side, square each side, subtract 2 from each side and then square each side, in that order. That would leave n=49
