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If the date is March 1, 2007, in how many whole years will the number representing the year be the smallest perfect square greater than 2007?

 Feb 14, 2019
 #1
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I'm not sure if you are going to like how I solved the problem, but I solved it anyways.

 

We already know that \(40^2\) is 1600 and that \(50^2\) is 2500, that means the answer is between 40 and 50. Seeing that 2000 (2007 rounds to 2000) is closer to 1600, we try if \(44^2\) will fit the answer. \(44^2\) apparently is 1936, so the next possible solution is 45. Seeing that \(45^2\)is 2025, we can know that \(\boxed{18} \) years after 2007 will be the answer

 

If somebody finds a better way to solve this, please post it.

 Feb 14, 2019
edited by CalculatorUser  Feb 14, 2019
 #2
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Take the square root of 2007 =~44.8 - round it up to the next whole number, or 45.

45^2 = 2025 - 2007 = 18 - years.

 Feb 14, 2019

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