The cyclic quadrilateral in the circle shown above is a square. The diameter of the circle is 5. Find the area of the green region.

Guest Jul 2, 2020

#1**+4 **

Since the square and the circle, share teh circle's diameter, the diagonal of the square is also 5. Therefore the length of the side of the square is \(\frac{5}{√2}\). So the area of the square is \((\frac{5}{√2})^2\) which equals \(\frac{25}{2}\).

Next, we figure out the area of the circle. Since the diameter is 5, the radius is \(\frac{5}{2}\). The area is pi multiplied by the radius sqaured.

So it would be 3.14 (In class, my teacher taught us to use 3.14 as pi) times \(\frac{25}{4}\)which equals at the end, 19.625! If it is incorrect, try typing the answer in terms of pi, see if that helps, or I might've done something wrong.

chickenwing Jul 2, 2020