+2862 I finished part of my essay so I decided to take a little break with math.
So the center of the circle is E.
1. We draw EA, which is the radius of the circle.
2. Now we connect the center to the midpoint of AD.
3. We set the hypotenuse of the triangle equal to X.
4. We know that the longer leg of the triangle is 5
5. We draw a line from center E to the midpoint of BC.
6. We know that is a radius. So the length of that is also X.
7. Since the side of the square is 10, we know that the line from center E to the midpoint of AD is 10-x
8. Using the pythagorean theorem, you set up the equation
\(5^2+(10-x)^2=x^2\)
9. Solve for X.
10. Use the circle formula to find the area of the circle using your value of X. Then you have the answer.
Not giving my answer, but when I solved it, I got a decimal (or fraction).
+2862 I finished part of my essay so I decided to take a little break with math.
So the center of the circle is E.
1. We draw EA, which is the radius of the circle.
2. Now we connect the center to the midpoint of AD.
3. We set the hypotenuse of the triangle equal to X.
4. We know that the longer leg of the triangle is 5
5. We draw a line from center E to the midpoint of BC.
6. We know that is a radius. So the length of that is also X.
7. Since the side of the square is 10, we know that the line from center E to the midpoint of AD is 10-x
8. Using the pythagorean theorem, you set up the equation
\(5^2+(10-x)^2=x^2\)
9. Solve for X.
10. Use the circle formula to find the area of the circle using your value of X. Then you have the answer.
Not giving my answer, but when I solved it, I got a decimal (or fraction).
