How many ordered pairs, (x,y), of positive integers satisfy the equation xy=144?
+130042 xy = 144
We can look at the factors of 144
These are
1 | 2 | 3 | 4 | 6 | 8 | 9 | 12 | 16 | 18 | 24 | 36 | 48 | 72 | 144
So
The ordered paIrs are
(1, 144)
(2, 72)
(3, 48)
(4, 36)
(6, 24)
(8, 18)
(9, 16)
(12, 12)
So.....reversing the first 7 pairs.....we have 7 + 7 + 1 = 15 possible pairs of (x, y)
