+0

# help :(

0
124
2
+102

Find all possible integer values of n such that the following system of equations has a solution for z:

\begin{align*} z^n &= 1, \\ \left(z + \frac{1}{z}\right)^n &= 1. \end{align*}

Jun 28, 2020

#1
+28021
+1

n = 0     should work

Jun 28, 2020
#2
0

Here's a hint: use exponential notation.

Jun 28, 2020