+0  
 
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Find all possible integer values of n such that the following system of equations has a solution for z:

\(\begin{align*} z^n &= 1, \\ \left(z + \frac{1}{z}\right)^n &= 1. \end{align*}\)
 

 Jun 28, 2020
 #1
avatar+26735 
+1

n = 0     should work  

 Jun 28, 2020
 #2
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0

Here's a hint: use exponential notation.

 Jun 28, 2020

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