How many integers satisfy $-4 \le 2x+1 \le 6$?
Thanks,
@Rom don't you need to apply the -1 to both sides of the inequality?
\(-4 \le 2x+1 \le 6\)
\(-5 \le 2x \le 5\)
\(-\frac{3}{2} \le x \le \frac{5}{2}\)
\(x \in \{-2, -1, 0, 1, 2, \}\)
\(\text {5 integers satisfy the inequality}\)
....
This is (currently) Rom’s final post. Here’s a link to a candlelight farewell.
GA
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