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How many integers satisfy $-4 \le 2x+1 \le 6$?

 

Thanks,

 Oct 18, 2019

Best Answer 

 #2
avatar+778 
+2

@Rom don't you need to apply the -1 to both sides of the inequality?

 

\(-4 \le 2x+1 \le 6\)

\(-5 \le 2x \le 5\)

\(-\frac{3}{2} \le x \le \frac{5}{2}\)

\(x \in \{-2, -1, 0, 1, 2, \}\)

\(\text {5 integers satisfy the inequality}\)

 Oct 18, 2019
edited by KnockOut  Oct 18, 2019
 #1
avatar+6045 
0

....

.
 Oct 18, 2019
edited by Rom  Oct 18, 2019
edited by Rom  Oct 18, 2019
 #3
avatar+1808 
+1

This is (currently) Rom’s final post. Here’s a link to a candlelight farewell.

 

 

GA

GingerAle  Oct 25, 2019
edited by GingerAle  Oct 28, 2019
 #2
avatar+778 
+2
Best Answer

@Rom don't you need to apply the -1 to both sides of the inequality?

 

\(-4 \le 2x+1 \le 6\)

\(-5 \le 2x \le 5\)

\(-\frac{3}{2} \le x \le \frac{5}{2}\)

\(x \in \{-2, -1, 0, 1, 2, \}\)

\(\text {5 integers satisfy the inequality}\)

KnockOut Oct 18, 2019
edited by KnockOut  Oct 18, 2019
 #4
avatar+1808 
0

deleted 

GingerAle  Oct 25, 2019
edited by GingerAle  Oct 25, 2019

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