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The solution of \(8x+1\equiv 5 \pmod{12}\) is \(x\equiv a\pmod{m}\) for some positive integers \(m\geq 2\) and a

 Jan 13, 2019
 #1
avatar+9466 
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I guess you are trying to ask what is the values of m and a.

\(8x + 1 \equiv 5\pmod{12}\\ 8x\equiv4\pmod{12}\\ 8x\equiv16\pmod{12}\\ x\equiv2\pmod{12}\)

 Jan 13, 2019

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