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How many different positive integers divisible by 4 can be formed using at least one of the digits 1, 2, 3 and 4 exactly once and no other digits? For example, 12 counts, but 512 does not.

 Oct 19, 2018
 #1
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+1

   4
{1, 2} | {2, 4} | | {3, 2} |(total: 3)
 {1, 2, 4} | {1, 3, 2} } | | {3, 1, 2} | | {3, 2, 4} |  {4, 1, 2} ... (total: 5)

{1, 3, 2, 4} | {1, 4, 3, 2} | | {3, 1, 2, 4} | | {3, 4, 1, 2} | | {4, 1, 3, 2} | ... (total: 5)

 

1 + 3 + 5 + 5=14 I get 14 integers divisible by 4

 Oct 19, 2018
 #2
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0

Add 1 as well and make it 15 numbers in total !!.

 Oct 19, 2018

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