+0  
 
0
33
2
avatar+418 

How many different positive integers divisible by 4 can be formed using at least one of the digits 1, 2, 3 and 4 exactly once and no other digits? For example, 12 counts, but 512 does not.

Logic  Oct 19, 2018
 #1
avatar
+1

   4
{1, 2} | {2, 4} | | {3, 2} |(total: 3)
 {1, 2, 4} | {1, 3, 2} } | | {3, 1, 2} | | {3, 2, 4} |  {4, 1, 2} ... (total: 5)

{1, 3, 2, 4} | {1, 4, 3, 2} | | {3, 1, 2, 4} | | {3, 4, 1, 2} | | {4, 1, 3, 2} | ... (total: 5)

 

1 + 3 + 5 + 5=14 I get 14 integers divisible by 4

Guest Oct 19, 2018
 #2
avatar
0

Add 1 as well and make it 15 numbers in total !!.

Guest Oct 19, 2018

31 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.